10 Principles that Brought me MILLIONS (It can work for you too)

10 Principles that Brought me MILLIONS (It can work for you too)

Kimia Isobutylene is a hydrocarbon used in the manufacture of synthetic rubber. When 0.847 g of isobutylene was subjected to combustion analysis, the gain in mass of the CO2 absorber was 2.657 g and that of the H2O absorber was 1.089 g. What is the empirical formula of isobutylene?

Isobutylene is a hydrocarbon used in the manufacture of synthetic rubber. When 0.847 g of isobutylene was subjected to combustion analysis, the gain in mass of the CO2 absorber was 2.657 g and that of the H2O absorber was 1.089 g. What is the empirical formula of isobutylene?

Answer:

CH₂₋

Explanation;

1) Determine the mass of each element in a given mass number of compounds or the mass percent of each element.

Equation of reaction question

                   subscript C x subscript H subscript y and O 2 produces subscript C O 2 and subscript H 2 O

Mass of space C spaced from space C O subscript 2 is equal to the numerator fraction 1 cross over 12 above the denominator 44 end of the fraction multiplied by cross 2 point 657 equals 0 comma 72 gram space Mass of space H spaced from space H subscript 2 O is equal to the numerator fraction 2 cross times 1 denominator 18 final fraction cross 1 comma 089 equals 0 comma 12 gram spaces

2) Divide the mass of each element by the relative atomic mass, thus obtaining the mole ratio of each atomic ratio. For example, the formula for the compound is: C subscript x H subscript y mole space C colon space mole space H double bond x colon spaced space y mass over Ar C colonic space mass over Ar H double bond x colon spaced space y fraction of numerator 0 comma 72 denominator over 12 end fractions colon space fractional space 0 comma 12 denominator more than 1 ending fraction equal to 0 comma 06 space colon 0 comma 12

3) Convert the obtained comparisons to simple integers.

x space colon space y space equals space 0 comma 06 space colon space 0 comma 12 space equals space 1 space colonize space 2

Therefore, the empirical formula for the compound is the subscript CH2.

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